My goal is to search a single column for a particular value in a CSV file and print splitted_line[2]
I have a CSV file that has 800+ rows. Column one has a list of numbers associated with each line. Shown below:
96,"Happy snappy chicken",-rhubarb,https://v.redd.it/kwarsqx9m1s51
97,"Party Located. Engaging",Mernerner,https://i.imgur.com/lNs61d9.jpg
98,"[TikTok] This conure likes to BONK",lilgothbabey,https://v.redd.it/l7mm4cakjtr51
99,"He escaped his outside cage and just made this little smug face",Molly_the_yorkie_poo,https://i.redd.it/naqfaoq801s51.jpg
100,"Little pie",Sweety_pie19,https://i.redd.it/s9i2xc06n0s51.jpg
101,"After a bad visit with the vet, Alex is back to his attention-seeking self!",jballen93017,https://i.redd.it/cfbyevqyozr51.jpg
My script below is supposed to search through that first column, and if the number == first column
then print the entire row. Except when I do this, it prints all 800+ rows. Any help?
import pyautogui
from datetime import datetime, time
import os, sys, random
import io
import csv
from time import sleep
folder_path = "PATH"
def upload_photo():
list = os.listdir(folder_path)
number_files = len(list) # Returns the number of files in a directory as an integer
try:
for i in range(number_files):
random_file = random.choice(os.listdir(folder_path)) # Chooses random file in folder
print(random_file) # Print file name
nfile = int(''.join(filter(str.isdigit, random_file.split('.')[0]))) # Splits the extention
print (nfile) # Prints the number associated with the image
break
except:
print("Hit except")
with open("output_reddit.csv", 'r') as csvfile:
for line in csvfile:
splitted_line = line.split(',')
if splitted_line[0] == nfile:
print(splitted_line[1])
upload_photo()