take one of the same elements in different strings

Question

I want to combine the three different series I have. I also need to provide singularity for each element. Output order is not important.Example 3 arrays:

a=["apple","banana","orange"]
b=["apple","banana"]
c=["cherry","grappe"]

result

result=["apple","banana","orange","cherry","grappe"]

Please clarify what the order of expected output is - you accepted an answer that explicitely gives a different order... — Thierry Lathuille, Oct 16 '20 at 13:39

score 2 · Answer 1 · answered Oct 16 '20 at 09:32

2

You can use set and do like this:

a=["apple","banana","orange"]
b=["apple","banana"]
c=["cherry","grappe"]

result = list(set(a + b + c))

>>> result = ["apple","banana","orange","cherry","grappe"]

answered Oct 16 '20 at 09:32

ParthS007

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score 1 · Answer 2 · answered Oct 16 '20 at 09:32

1

a = ["apple", "banana", "orange"]
b = ["apple", "banana"]
c = ["cherry", "grappe"]

lst = list(set(a + b + c))
print(lst)

['banana', 'apple', 'cherry', 'grappe', 'orange']

Check out the docs for set to understand what it is doing.

answered Oct 16 '20 at 09:32

felipe

7,324
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Is it any different from my answer? – ParthS007 Oct 16 '20 at 09:33
Other than detailing where to find the documentation for set, and being 30s after yours, nope, doesn't seem like it. :) – felipe Oct 16 '20 at 09:34
You can edit my answer adding doc link to have only one answer if that's fine with you :) – ParthS007 Oct 16 '20 at 09:35

score 1 · Accepted Answer · answered Oct 16 '20 at 09:33

1

You can use itertools.chain then convert to set to remove duplicates and then convert back to list (done a sort too):

import itertools
a=["apple","banana","orange"]
b=["apple","banana"]
c=["cherry","grappe"]
d = sorted(list(set(list(itertools.chain(a,b,c)))))
print(d)

answered Oct 16 '20 at 09:33

Wasif

14,755
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The expected output has the output sorted by order of appearance, this would sort in alphabetical order. – Thierry Lathuille Oct 16 '20 at 13:38

score 1 · Answer 4 · answered Oct 16 '20 at 09:37

If you want to keep the order of first appearance, as your sample output suggests, one way is to create a dict with your data as keys, taking advantage of the fact that dicts are ordered since Python 3.7:

from itertools import chain

a = ["apple","banana","orange"]
b = ["apple","banana"]
c = ["cherry","grappe"]

d = {key: None for key in chain(a, b, c)}
result = list(d.keys())

print(result)
# ['apple', 'banana', 'orange', 'cherry', 'grappe']

score 1 · Answer 5 · answered Oct 16 '20 at 09:39

a = ["apple", "banana", "orange"]
b = ["apple", "banana"]
c = ["cherry", "grappe"]
result = a + b + c  # marge all lsit
result = list(dict().fromkeys(result))  # remove duplicate
print(result)

Reference: https://www.w3schools.com/python/python_howto_remove_duplicates.asp

score 0 · Answer 6 · answered Oct 16 '20 at 09:34

0

You can use set to get rid of duplicates:

list(set(a+b+c))

answered Oct 16 '20 at 09:34

Szymon

91
6

take one of the same elements in different strings

6 Answers6