Numpy exact value

Question

How do I get the initial value when a square rooted value is squared again in python?

For example :

np.square((np.sqrt(2)))

but the terminal gives the '2.0000000000000004'.

My opinion is about to square the value first, but can any correction be made in this code representation?

Answer 1

>>> round(np.square((np.sqrt(2))), 2)
2.0