How to check if a file's window is closed/open Python?

Question

How can I check when a file window is closed? I tried this:

import time
import os

path = input()
os.startfile(request)

try:
    file_path = open(path, 'rb')
except Exception:
    done = True
    while done:
        if file_path.closed:
            done = False
        time.sleep(SLEEP_TIME)

So the file starts before I start checking if the file is closed. Then, I open the file again, and because its open already, an exception should pop up, where I'm looping until the file is closed. I don't know whether the indication I made is right or not.

Please help!!! I'm desperate!!!

You can open a file many times. But what do you mean by "file window"?? — Thierry Lathuille, Oct 18 '20 at 07:03
Check the answers https://stackoverflow.com/questions/6825994/check-if-a-file-is-open-in-python — Vaebhav, Oct 18 '20 at 07:04
If you get an exception when calling `open()`, the variable is never assigned, so you can't refer to `file_path`. — Barmar, Oct 18 '20 at 07:04
My bad. I mean a panel. When you click twice on a file and it opens up with the default program. — Tomer Bar, Oct 19 '20 at 10:14

score 0 · Answer 1 · answered Oct 18 '20 at 07:07

You can't use file_path in the except: block, because the variable isn't assigned if open() raises an exception.

You should put the loop around the try/except, not inside the except.

while True:
    try:
        file_path = open(path, 'rb')
        break
    except:
        time.sleep(SLEEP_TIME)

Sadaf Shafi · Answer 2 · 2020-10-18T07:17:02.727

0

It will open the file only once, and if the file is already open it will use the already opened fie

import time

import os

path = 'bescom-17-apr.pdf'

try:
   with open(path, "r") as file:
       print("opened file")
except IOError:
   print("file not found")

edited Oct 18 '20 at 07:17

answered Oct 18 '20 at 07:09

Sadaf Shafi

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How to check if a file's window is closed/open Python?

2 Answers2