Servlet doGet return 404 on a simple get method?

Question

I have a simple doGet method on a hyperlink to direct a view cart summary. It works if I run on the servlet the path is,

 http://localhost:9090/WebApp/view_cart

whereas if I run on the JSP page when I click the below hyperlink, The path is

<form method="GET"> <a href="view_cart"> view cart </a> </form>

http://localhost:9090/WebApp/frontend/view_cart

Here is a doGet method, how can I get the correct path to show the /view_cart page??

@WebServlet("/view_cart")
public class ViewCartServlet extends HttpServlet {
    private static final long serialVersionUID = 1L;

    public ViewCartServlet() {
        super();
    }

    protected void doGet(HttpServletRequest request, HttpServletResponse response)
            throws ServletException, IOException {

        response.getWriter().append("Served at: ").append(request.getContextPath());
                    
        response.setContentType("text/html");

        String viewCart = "frontend/shopping_cart.jsp";
        RequestDispatcher rd = request.getRequestDispatcher(viewCart);
        rd.forward(request, response);    
    }

}

What about linking to `${request.contextPath}view_cart)` in your JSP file? — dan1st, Oct 19 '20 at 14:55

score 1 · Answer 1 · answered Oct 19 '20 at 14:53

1

Replace

<a href="view_cart">

with

<a href="/view_cart">

So that the path can become the-context-path/view_cart

answered Oct 19 '20 at 14:53

Arvind Kumar Avinash

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I need to go to root then back to the folder that I store the jsp like this cart – Stu_Dent Oct 20 '20 at 07:45
@Stu_Dent - Yes, that's the idea. I hope your problem is solved. – Arvind Kumar Avinash Oct 20 '20 at 07:50

Servlet doGet return 404 on a simple get method?

1 Answers1