Scanning a directory to list the name of all files

Question

I have a big folder in which there are many subfolders. Each of those subfolders can also have some subfolders ( number can be different ) in it. This goes on for some levels. And in the end, there is a text file. How can I make a python program that traverses the entire directory as deep as it goes and prints the name of the text file? In simpler terms, I want to navigate through the directory as long as there are no more sub-directories?

Does this answer your question? [How do you walk through the directories using python?](https://stackoverflow.com/questions/2922783/how-do-you-walk-through-the-directories-using-python) — funie200, Oct 22 '20 at 11:41

score 3 · Accepted Answer · answered Oct 22 '20 at 11:42

Use os.walk.

For instance, creating a deep hierarchy like

$ mkdir -p a/b/c/d/e/f/g
$ touch a/b/c/d/e/f/g/h.txt

and running

import os
for dirname, dirnames, filenames in os.walk('.'):
    for filename in filenames:
         filepath = os.path.join(dirname, filename)
         print(filepath)

yields

./a/b/c/d/e/f/g/h.txt

– do what you will with filepath.

Another option, if you're using Python 3.5 or newer (and you probably should be) is glob.glob() with a recursive pattern:

>>> print(glob.glob("./**/*.txt", recursive=True))
['./a/b/c/d/e/f/g/h.txt']

Scanning a directory to list the name of all files

1 Answers1