Is there a regex where if first expression is valid then check for next

Asked Oct 23 '20 at 06:29

Active Oct 23 '20 at 07:22

Viewed 41 times

For eg.

set "var" "value"

This will always be in the same order.

I am using "(.+?)" to get "var" and "value".

But I only want to match this only when it starts with "set".

base "as" "asd" - Should not match
set "as" "asd" - Match and return ("as", "asd")

edited Oct 23 '20 at 07:22

41686d6564 stands w. Palestine

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asked Oct 23 '20 at 06:29

user2113551

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`/set ("var") ("value")/`? – VLAZ Oct 23 '20 at 06:36
this will match the whole line. I just want var, value to match only if it starts with set. – user2113551 Oct 23 '20 at 06:49
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What programming language (or regex flavor) are you using? It's important to mention that (and use the appropriate tags) when posting a regex question. Not all regex features are supported in all flavors. – 41686d6564 stands w. Palestine Oct 23 '20 at 06:53
Also, are the values you want to match (the ones enclose in quotations) always consecutive or can they appear anywhere in the string? Are there always two of them? Or an arbitrary number? – 41686d6564 stands w. Palestine Oct 23 '20 at 06:58
I am using Java and they will always be consecutive and only two matches. – user2113551 Oct 23 '20 at 07:06
If they're always two, then the easiest way would be to use `set "(.+?)" "(.+?)"` and find your values in the 1st and 2nd capturing groups. If they're more then two or you don't want to use multiple groups, you could use `(?<=set |\G )"(.+?)"`. Here's a [demo](https://regex101.com/r/5khrEB/1). – 41686d6564 stands w. Palestine Oct 23 '20 at 07:13
Side note: it's usually better to use `"[^"]+"` instead of `".+?"` for a couple of reasons. One of which is that the latter would match `"""` while the former wouldn't. – 41686d6564 stands w. Palestine Oct 23 '20 at 07:21
You already know how to capture parts of regex but you seem to be unaware of how to access these groups, see the linked thread to learn about that. – Wiktor Stribiżew Oct 23 '20 at 07:35
Thanks this works for me set "(.+?)" "(.+?)" – user2113551 Oct 24 '20 at 11:36

Is there a regex where if first expression is valid then check for next

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