How to get all of an objects properties, if one property found?

Question

I have an array with objects, which are props on a react component

this.props.items = [
    {make: Audi, model: A1, premiere: true},
    {make: BMW, model: X1, premiere: false},
    {make: Merc, model: C1, premiere: false}
]

I want to grab the details of the first object because it is

'premiere: true'

Which I can do like so:

this.props.items.map(x => x.premiere);

How can I grab all of the objects remaining keys and values and store them in them in state of the component?

{make: Audi, model: A1, premiere: true}

Through load dash lib : let filteredTimes = _.map(items, function(o) { if (o.premiere == true) return o; }); — abhay, Oct 23 '20 at 11:08

score 2 · Accepted Answer · answered Oct 23 '20 at 10:15

2

Use Array.prototype.filter instead of Array.prototype.map

answered Oct 23 '20 at 10:15

netizen

1,028
7
19

score 2 · Answer 2 · answered Oct 23 '20 at 10:16

2

change this.props.items.map(x => x.premiere); to this.props.items.filter(x => x.premiere);

answered Oct 23 '20 at 10:16

Quang Thái

649
5
17

How to get all of an objects properties, if one property found?

2 Answers2