reverse engineering in C; bomb lab

Question

I am doing a lab for my cs class and we are reverse engineering a "binary bomb". I am confused on a few assembler instructions. If anyone could explain what these do and how the work I would greatly appreciate it.

lea   0x10(%rbx), %rbp.

Im pretty sure rbx is supposed to hold the address of rbp, but im confused on the 0x10 argument.

mov   0x4(%rbx), %eax.

Same thing as above, don't understand what the 0x4 argument is.

Also: https://en.wikibooks.org/wiki/X86_Assembly/GAS_Syntax#Address_operand_syntax — Marco Bonelli, Oct 24 '20 at 20:21

score 1 · Accepted Answer · answered Oct 24 '20 at 20:50

1

These are offsets (0x10 = 16bytes and 0x4=4bytes) to the pointers in rbp and eax. Most likely iterating over elements in an array/vector.

answered Oct 24 '20 at 20:50

Gabriel

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reverse engineering in C; bomb lab

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