Printing functions in cpp

Question

Why is it that any time i print a function in cpp, it prints 1. i.e

#include <iostream>
using namespace std;
void f1(){
   cout<<"called function f";
}
int f2(){
   cout<<"called f2";
   return 1;
}
int main(){
   cout << f2 <<endl; // prints 1
   cout << f1 <<endl; // still prints 1
}

Im just wondering why it prints 1.

Thanks for your help

`f` is not defined. Please post a [Minimal, Reproducible Example](https://stackoverflow.com/help/minimal-reproducible-example). — MikeCAT, Oct 25 '20 at 13:17
You want to call the functions, not to output their function pointers: `cout << f2() < — πάντα ῥεῖ, Oct 25 '20 at 13:19

score 1 · Accepted Answer · answered Oct 25 '20 at 13:20

It seems it is judging if the functions (converted to pointers to functions) are not null, returning true, and printing true as 1. This can be confirmed by adding cout << std::boolalpha; and seeing the the output is changed to true.

#include <iostream>
using namespace std;
void f1(){
   cout<<"called function f";
}
int f2(){
   cout<<"called f2";
   return 1;
}
int main(){
   cout << std::boolalpha;
   cout << f2 <<endl; // prints true
   cout << f1 <<endl; // also prints true
}

Thanks for the answer but why the down vote – Ekure Edem Oct 26 '20 at 15:13 — Ekure Edem, Oct 26 '20 at 15:13

Printing functions in cpp

1 Answers1