I have just started learning super basic Python this week. Look at my basic code for entry ticket in a park

Question

Ticket price depends on age. I am getting an error "invalid literal for value with base 10" in the line

age=int(age)

What does this error mean and how can I solve it? please fix indentation error (if any)

name="\t\n\n WHAT IS YOUR NAME?\t\n\t\t\t"
input(name)
name=str(name)
gender = "\nWhat is your GENDER (M/F) \t\n\t\t\t"
input(gender)
gender=str(gender)
age = "\t\n\tWhat is your age\t\n\t\t\t"
input(age)
age= int(age)
if gender == 'm ':
 gd="Mr. "
elif gender == 'f':
gd="Ms. "
else :
  gd = "_"

price = ['free for kid $0' , '$ 10' , '$15']
if age<=3:
  print("Hello  " + gd + name.title() + "  your Ticket fee is  " + price[0])
elif age <= 12:
  print("Hello "+gd+ name.title() + "  your Ticket fee is  " + price[1])
else:
 print("Hello "+gd+ name.title() + "  your Ticket fee is  " + price[2])

This is an excellent opportunity for you to read this: [How to debug small programs](https://ericlippert.com/2014/03/05/how-to-debug-small-programs/) — mkrieger1, Oct 27 '20 at 10:28
Set a breakpoint in this line `age= int(age)` and check the value of `age`. You will be surprised. — Thomas Sablik, Oct 27 '20 at 10:29
If you don't know what "breakpoint" means read this: https://stackoverflow.com/questions/25385173/what-is-a-debugger-and-how-can-it-help-me-diagnose-problems — mkrieger1, Oct 27 '20 at 10:31
And then this: https://stackoverflow.com/questions/4929251/how-to-step-through-python-code-to-help-debug-issues — mkrieger1, Oct 27 '20 at 10:31

score 0 · Answer 1 · answered Oct 27 '20 at 10:33

0

Your code is wrong from the basics. input is the keyword that takes the input from the user as well as shows the input message to the user. You need to store the value to a variable.

So your code should be like that,

name_prompet = "\t\n\n WHAT IS YOUR NAME?\t\n\t\t\t"
name = input(name_prompet)

same it should be with the age,

age_prompet = "\t\n\tWhat is your age\t\n\t\t\t"
age = input(age)

SO at age = int(age) technically you are trying to convert a string into int that's why it's an error.

Tell me if you need anything else.

answered Oct 27 '20 at 10:33

Muhammad Usman Bashir

66
1
6

what should i do so that this program asking name gender and age should continue without ending at "Hello Mr XYZ your ticket fee is **" – Noob_python Oct 27 '20 at 10:46
you can use a while loop for that purpose. – Muhammad Usman Bashir Oct 27 '20 at 14:37

score 0 · Accepted Answer · answered Oct 27 '20 at 10:42

0

Hi i am also new in Python but as i understand

1- age = "\t\n\tWhat is your age\t\n\t\t\t"
2- input(age)
3- age= int(age)

you can change as below

age = int(input("\t\n\tWhat is your age\t\n\t\t\t"))

line means age is a string which containt this data
read console and set to age variable
try to convert to int and set as same variable

string can carry multi type variable so should be carryfully.

BTW:

for gender 'f' and 'F' is different for python you can add OR condition.
try and catch is good for converting data

answered Oct 27 '20 at 10:42

doni_darko

16
1

how to make inputs 'f and F " act same – Noob_python Oct 27 '20 at 10:49
if gender == 'm ' or gender=='M': – doni_darko Oct 27 '20 at 11:15

I have just started learning super basic Python this week. Look at my basic code for entry ticket in a park

2 Answers2