Regex get only full matching (Not grouping)

Question

I have a regex which looks like this:

[@|#](.*?)\s

What I basically want is, split matching regex into arrays.

So I use the following code:

var testString = "Hi this is a test @info@test.com and @martin we have to go."
console.log(testString.split(/(\@|\#)(.*?)\s/));

The result what I get looks like this:

["Hi this is a test ", "@", "info@test.com", "and ", "@", "martin", "we have to go."]

What I actually want is:

["Hi this is a test ", "@info@test.com", "and ", "@martin", "we have to go."]

Please see [Use of capture groups in String.split()](https://stackoverflow.com/q/21419530/4642212). — Sebastian Simon, Oct 27 '20 at 12:03
If you need `@info@test.com` into your array then `split` is not for you. `Split` doesn't include the `separator` into the resulting array. — Sajeeb Ahamed, Oct 27 '20 at 12:08

score 2 · Accepted Answer · answered Oct 27 '20 at 11:59

Don't use split, use match:

testString.match(/[@#]\S+|[^@#]+/g)
// ["Hi this is a test ", "@info@test.com", " and ", "@martin", " we have to go."]

This regex simply matches all non-spaces after an @ or a #, or it matches all non-@ or # characters, effectively splitting it into chunks.

score 2 · Answer 2 · answered Oct 27 '20 at 12:07

2

You could use split by placing [#@] inside the capture group followed by matching 1+ non whitespace chars ([#@]\S+)

let s = "Hi this is a test @info@test.com and @martin we have to go.";
console.log(s.split(/([#@]\S+)/));

answered Oct 27 '20 at 12:07

The fourth bird

2 Answers2