python make multiple lists of one list

Question

in PYTHON i have one list and i want to make from it a multiple lists, for every item i want him to create a list with the other items

my initial list :

cities = ['Chevalley', 'A.Gharmoul 1', 'El Madania']

then i want the output to be :

[
  ['Chevalley', 'A.Gharmoul 1'],
  ['Chevalley','El Madania'],
  ['A.Gharmoul 1', 'El Madania']
]

itertools might help you out. https://docs.python.org/3/library/itertools.html#itertools.combinations look at this documentation — Ganesh Tiwari, Oct 27 '20 at 12:20
Does this answer your question? [How to get all possible combinations of a list’s elements?](https://stackoverflow.com/questions/464864/how-to-get-all-possible-combinations-of-a-list-s-elements) — Tomerikoo, Oct 27 '20 at 12:25
@ilyesBourouba Let me know, what do you think of my answer. Now I am planning to delete my answers which are not useful for the question (No upvotes answers) — Sivaram Rasathurai, Nov 01 '20 at 02:54

score 1 · Accepted Answer · answered Oct 27 '20 at 12:26

1

The below code will help you to create the resultant list you are looking for:

items = ['Chevalley', 'A.Gharmoul 1', 'El Madania']
res = [[items[i],items[j]] for i in range(len(items)) for j in range(i+1, len(items))]
print(res)

answered Oct 27 '20 at 12:26

Ananth

787
5
18

score 1 · Answer 2 · answered Oct 27 '20 at 12:27

result_list = []
for i in ['Chevalley', 'A.Gharmoul 1', 'El Madania']:
    for j in ['Chevalley', 'A.Gharmoul 1', 'El Madania']:
        if i != j:
            result_list.append([i, j])

It should iterate over every possible pairing while ignoring pairing element with itself.

score 0 · Answer 3 · answered Oct 27 '20 at 12:27

while this isn't the same it is pretty close to what you are looking for.

import itertools
a = ['Chevalley', 'A.Gharmoul 1', 'El Madania']
result = list(itertools.combinations(a,2)) # number is the amount of items you want in the resultant tuple

result will have tuples of length 2 in a list.

score 0 · Answer 4 · answered Oct 27 '20 at 12:27

Below should do it:

l  = ['Chevalley', 'A.Gharmoul 1', 'El Madania']
n = [[l[i], l[j]] for i in range(0, len(l) - 1, 1) for j in range(i + 1, len(l), 1)]

n will equate to:

[['Chevalley', 'A.Gharmoul 1'],
 ['Chevalley', 'El Madania'],
 ['A.Gharmoul 1', 'El Madania']]

score 0 · Answer 5 · answered Oct 27 '20 at 12:28

nested for loops does your work

list1 =['Chevalley', 'A.Gharmoul 1', 'El Madania']

output =[]

for i in range(len(list1)):
 for j in range(i+1,len(list1)):
  output.append([list1[i],list1[j]]) 

print(output)#[['Chevalley', 'A.Gharmoul 1'],['Chevalley','El Madania',['A.Gharmoul 1', 'El Madania']]

score 0 · Answer 6 · answered Oct 27 '20 at 12:34

0

You can use itertools and convert the output tuples into lists:

import itertools

new = [ list(el) for el in itertools.combinations(['Chevalley', 'A.Gharmoul 1', 'El Madania'], 2) ]

answered Oct 27 '20 at 12:34

hasleron

499
3
10

python make multiple lists of one list

6 Answers6