how can validate phone number with regex

Question

I'm trying to validate the following phone number with regex:

1) +415XXXXXXXX
2) 00415XXXXXXXX
3) 41 5XXXXXXXX
4) 41 05XXXXXXXX
5) 05XXXXXXXX
6) 5XXXXXXXX

I tries this expression

^\+?41?\s?0?5\d{8}$

and was able to validate situations (1,3,4), could any one help me to adjust the above one to be able to cover the rest scenarios?

Your regex seems to only validate phone numbers that begin with "41", which explains why 1, 3, 4 are the only ones that match. I'm not sure what the conditions of your problem are, since you can technically write a regex to accept any string of numbers as "phone numbers". — General Poxter, Oct 28 '20 at 15:40
Use `^(?:(?:\+|00)415|41 0?5|0?5)\d{8}$` ([demo](https://regex101.com/r/IDkscC/2)) — Wiktor Stribiżew, Oct 28 '20 at 15:40
that was great, thanks, i didn't know what to use to make the number start with 0041 or +41 :) — RAZ, Oct 28 '20 at 15:52

score 0 · Answer 1 · answered Oct 28 '20 at 15:44

One "brute force" approach would be to just handle each prefix separately in an alternation:

var nums = ["+41512345678", "0041512345678", "41 512345678", "41 0512345678", "0512345678", "512345678", "2128675309"];
nums.forEach(function(number) {
    console.log(number + " passes? " +
/^(?:\+415|00415|41 0?5|0?5)\d{8}$/.test(number));
});

how can validate phone number with regex

1 Answers1