(intermediate value) is not a function when running anonymous async iify in Node.js

Asked Oct 29 '20 at 14:15

Active Oct 29 '20 at 14:18

Viewed 14 times

Sorry this might seem like a stupid question but I have no idea why it's throwing this error, this is the entire code in an index.js file that I try to run!

(async() => {
  console.log('hi');
})();

And it returns this error!

(intermediate value) is not a function`

When I turn into a regular async function and call it it works fine.

edited Oct 29 '20 at 14:18

Quentin

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asked Oct 29 '20 at 14:15

RogerKint

3

What is the line above your `(async () => {`? Sounds almost certain to be an ASI issue – CertainPerformance Oct 29 '20 at 14:17
@CertainPerformance wow I added a semi colon to the function above and it fixed it. A collegue recently told me that you pretty much don't have add to semi colons but clearly that's wrong. – RogerKint Oct 29 '20 at 14:20
2

Definitely wrong. Unless you're an expert and can avoid the pitfalls of ASI on sight, use semicolons, else you'll occasionally run into weird bugs like these. – CertainPerformance Oct 29 '20 at 14:20
Cheers thanks!! I'll read about ASI – RogerKint Oct 29 '20 at 14:25

(intermediate value) is not a function when running anonymous async iify in Node.js

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