How to access the values from strings.xml dynamically?

Question

What I want to do is to get a specific text from strings.xml dynamically. I think it will involve to access an object variable dynamically. There will be a function like:

public void getDynamicString(int level) {
  text.setText(R.string.levelText_+level);
}

And in strings.xml there will be <string name="levelText_5">Text level 5</string>

I would rather not create a list with all the text resources. Can one do this in Java/Android.

score 2 · Accepted Answer · answered Jun 23 '11 at 21:31

2

Use the method getIdentifier(name, defType, defPackage) of the Resources class to get the id of a resource by name. Then you can do a normal getString(id) from the same class.

EDIT: a bit of Googling revealed this: this. You can find sample usage there.

answered Jun 23 '11 at 21:31

Savvas Dalkitsis

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Dante · Answer 2 · 2018-04-03T13:35:01.407

0

I had the same problem and I fixed it using this

okey , whenever you want to access a string from strings.xml dynamically and what i mean by that is to avoid using getResources().getString(R.id.stringId) ,you create a string in which you can manipulate dynamically however you want in our case uriq ("stupid variable name") and then you create resource object which is in my example level_res and initialize it then you use this method called getIdentifier() which accepts your dynamic string as a parameter ,now u simply pass your ressource to the method getstring(mysttring)

 String uriq="level"+level_num;
 level_res=getResources();
 int mystring=getResources().getIdentifier(uriq,"string",getPackageName());
 String level=level_res.getString(mystring);

edited Apr 03 '18 at 13:35

answered Apr 02 '18 at 17:53

Dante

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Can you explain your solution? – Michael Apr 02 '18 at 18:15
uriq represents the string that changes dynamically by channging level_num ,so all you need to do is use the method getIdentifier() to get the appropriate string – Dante Apr 02 '18 at 22:54
okey , whenever you want to access a string from strings.xml dynamically and what i mean by that is to avoid using getResources().getString(R.id.stringId) ,you create a string in which you can manipulate dynamically however you want in our case uriq ("stupid variable name") and then you create resource object which is in my example level_res and initialize it then you use this method called getIdentifier() which accepts your dynamic string as a parameter ,now u simply pass your ressource to the method getstring(mysttring) – Dante Apr 03 '18 at 13:04
Ezio please add that information to your answer, not in the comments :) – Michael Apr 03 '18 at 13:32
ah sorry , i thought you wanted explanation xD – Dante Apr 03 '18 at 13:37

score 0 · Answer 3 · answered Jun 23 '11 at 21:29

0

Try: getResources().getString(R.id.stringId).

answered Jun 23 '11 at 21:29

Mandel

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Yes, but the question is how to get that dinamically? I would have to concatenate somehow. – fruehbier Jun 23 '11 at 21:31
Perhaps, you can have an array of strings in which case you need not concatenate. – Mandel Jun 23 '11 at 21:33

Kenny · Answer 4 · 2011-06-23T21:40:58.323

0

All you have to do is call

this.getString(R.string.levelText_5)

If your in an area of the program in which you have access to a Context or Application, such as a ListAdapter call:

context.getString(R.string.levelText_5)

or

application.getString(R.string.levelText_5)

if you have no access to the context or application then call:

getResources().getString(R.String.levelText_5);

To do it dynamically call:

String name = "levelText_"+level;
int id = getIdentifier(name, "string", "com.test.mypackage");
getResources().getString(id);

edited Jun 23 '11 at 21:40

answered Jun 23 '11 at 21:30

Kenny

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yeah, but 5 will come as a parameter, in a variable. – fruehbier Jun 23 '11 at 21:32

score 0 · Answer 5 · answered Jun 23 '11 at 21:32

0

You should look at using getIdentifier(String, String, String) of the Resources class.

answered Jun 23 '11 at 21:32

nicholas.hauschild

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How to access the values from strings.xml dynamically?

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