struct receiver to outside function

Question

I really don't understand this code

I think I understand how receiver work but when /foo gets requested, why that struct becomes receiver to SERVEHTTP which is never called? If this is how http works, is this typical style use of receiver?

main go

import "net/http"

type fooHandler struct {
    Message sstring
}

func (f *fooHandler) ServerHTTP(w http.ResponseWriter, r *http.Request) {
    w.Write([]byte(f.Message))
}

func main() {
    http.Handle("/foo", &fooHandler{Message: "Hello world"})
}

This might help [servehttp-work](https://stackoverflow.com/questions/49668070/how-does-servehttp-work) — abhijit gupta, Oct 31 '20 at 20:47
thank LINK was so good @abhijitgupta I feel like I understand MUCH better now.. thank you. — user3502374, Nov 03 '20 at 21:16

score 0 · Answer 1 · edited Nov 01 '20 at 09:24

0

First: it should be ServeHTTP, not ServerHTTP

With ServeHTTP method, fooHandler is a struct that implements http.Handler interface. Because of this, you can pass &fooHandler to http.Handle, and when that URL is loaded, the ServeHTTP method of fooHandler will be called.

edited Nov 01 '20 at 09:24

Peter

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answered Oct 31 '20 at 20:39

Burak Serdar

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struct receiver to outside function

1 Answers1