Instruction gets executed before the one above in Node.js

Question

When I execute the code below:

const https = require('https');

const req = https.get('https://www.google.com', (res) => {
   console.log('message');
})

console.log('message2');

The output I get is:

message2
message

Why is that?

Does this answer your question? [How do you make javascript code execute \*in order\*](https://stackoverflow.com/questions/2637626/how-do-you-make-javascript-code-execute-in-order) — Rashomon, Nov 01 '20 at 16:33
you need to watch [this video](https://www.youtube.com/watch?v=8aGhZQkoFbQ) to get more understanding of asynchronous behaviour — Naren, Nov 01 '20 at 16:34

score 0 · Accepted Answer · answered Nov 01 '20 at 16:32

It's because https.get is asynchronous, so NodeJs don't wait this call and immediately executes console.log('message2');. That way we can not to wait async call completion and continue doing something. After that request finished successfully you'll get console.log('message');

Instruction gets executed before the one above in Node.js

1 Answers1