How to sort a list using digits in each item of the list? Python

Question

I have the following list:

['God: 250', 'Noob: 0', 'Bot: 20']

I would like to sort the list in ascending order using the numbers at the end of each element. The end product should look something like this:

['Noob: 0', 'Bot: 20', 'God: 250']

I have had a look at other solutions in this question but have had no luck. Any help is appreciated.

SOLUTION

list.sort(key=lambda x: int(x.split(":")[1].strip()))

`a.sort(key=lambda x: int(x.split(":")[1].strip()))` – Abdul Niyas P M Nov 02 '20 at 09:29 — Abdul Niyas P M, Nov 02 '20 at 09:29
That works, thank you. I'll update the question. – ahmedquran12 Nov 02 '20 at 09:32 — ahmedquran12, Nov 02 '20 at 09:32

score 0 · Accepted Answer · answered Nov 02 '20 at 09:40

0

print(sorted(myList, key=lambda x: int("".join([i for i in x if i.isdigit()]))))

answered Nov 02 '20 at 09:40

meltemarslan

1 Answers1