Regex detection part of string

Question

How can I detect this part: /table/LEKPOOZZZCV/LSK1633923 from string variable:

'<a class="live-data__header" href="/table/LEKPOOZZZCV/LSK1633923"><div class="table_names" data-v-fc63c1b6=""><span class="table_names__name" data-v-fc63c1b6="" title="W............

using regex expression?

`(?<=href=\")[^\"]+` but you should really use an xml/html parser and XPath the data you need. — MonkeyZeus, Nov 02 '20 at 19:09
Do you _have_ to use a regex here? I'd use an XML parser and then get the `href` attribute from the `` tag. — gen_Eric, Nov 02 '20 at 19:10
@Rocket Hazmat pls, can you send how you use XML parser, Im newbie in this field... have problems with this — 314mip, Nov 02 '20 at 19:11

Barbaros Özhan · Accepted Answer · 2020-11-02T20:57:54.540

0

You can use findall such as

import re
s = '<a class="live-data__header" href="/table/LEKPOOZZZCV/LSK1633923"><div class=....'
print(re.findall('href="([^"]*)"', s))

in order to get as a list or

l = re.findall('href="([^"]*)"', s)
for i in l:
    print(i)

to get as a string

edited Nov 02 '20 at 20:57

answered Nov 02 '20 at 19:11

Barbaros Özhan

59,113
10
31
55

1

`href="([^"]*)"` retrieves too much if OP doesn't know how to access capture groups. – MonkeyZeus Nov 02 '20 at 19:37

Regex detection part of string

1 Answers1