Drop un-needed decimal ".0"

Question

I'm making a simple calculator and I am having an issue with it showing a decimal on what I want to just be a whole number. For example, if the entered expression is "50 + 50" the answer will come out "100.0". I understand that it's happening because my output is set as a double, but I can't figure out how to convert those numbers to integer only when the answer is ".0".

My output answer code:

fun equal (view: View) {
    secondnum = editText.text.toString()
    decpressed = 0
    var sum = 0.0
    when (op) {
        "+" -> {sum = (firstnum.toDouble() + secondnum.toDouble())}
        "-" -> {sum = (firstnum.toDouble() - secondnum.toDouble())}
        "*" -> {sum = (firstnum.toDouble() * secondnum.toDouble())}
        "/" -> {sum = (firstnum.toDouble() / secondnum.toDouble())}
    }
    editText.setText(sum.toString())
    textView.text = "$firstnum $op $secondnum ="
    zero = true
}

Does this answer your question? [Print float with two decimals unless number is a mathematical integer](https://stackoverflow.com/questions/64102602/print-float-with-two-decimals-unless-number-is-a-mathematical-integer) — Adam Millerchip, Nov 05 '20 at 01:22
having trouble figuring out how to implement into my program — NikkoNikkoNii, Nov 05 '20 at 01:33
I added an answer. You can just add `.removeSuffix(".0")` after `toString()`. — Adam Millerchip, Nov 05 '20 at 01:34
When the answer is that simple it makes me feel dumb I had to ask lol thank you very much! — NikkoNikkoNii, Nov 05 '20 at 01:40

score 4 · Accepted Answer · answered Nov 05 '20 at 01:28

4

You can use removeSuffix:

fun main() {
    println(100.5.toString().removeSuffix(".0"))
    println(100.0.toString().removeSuffix(".0"))
}

Output:

100.5
100

answered Nov 05 '20 at 01:28

Adam Millerchip

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Drop un-needed decimal ".0"

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