C++ template inheritance visibility lost in derived class

Asked Nov 05 '20 at 16:14

Active Nov 05 '20 at 16:17

Viewed 20 times

I am struggling with a very simple template design:

template <typename T>
class A {
public:
    int i=4;
};

template <typename T>
class B : public  A<T> {
public:
    int f() {return i;}
};

The compiler says that i is not declared in the scope of B. I can solve it by prefixing with A:

int f() {return A<T>::i;}

But, as this is an extract of a more general design, I want to understand the problem: B<T> has A<T> as a father so i should be accessible without prefixing?

I think it must be a trivial problem but I can't see the solution.

edited Nov 05 '20 at 16:17

asked Nov 05 '20 at 16:14

Javaddict

`this->i` would be enough – Ted Lyngmo Nov 05 '20 at 16:16
Yes but it doesn't explain why it is impossible to access i directly. – Javaddict Nov 05 '20 at 16:45
No, I was searching for the duplicate question with answers that _does_ explain it - but Brian found it first. Just read the answers in that link and it should be explained. – Ted Lyngmo Nov 05 '20 at 16:47

C++ template inheritance visibility lost in derived class

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