How can I do it with for loop (Python)?

Question

It's a simple question, but I can't find the solution. How can I do it with for loop? (In a shorter way.)

nfo1 = str(nfolist[0])
nfo2 = str(nfolist[1])
nfo3 = str(nfolist[2])
nfo4 = str(nfolist[3])
nfo5 = str(nfolist[4])
nfo6 = str(nfolist[5])
nfo7 = str(nfolist[6])
nfo8 = str(nfolist[7])
nfo9 = str(nfolist[8])
nfo10 = str(nfolist[9])
nfo11 = str(nfolist[10])

I think you should see this old question. https://stackoverflow.com/questions/6181935/how-do-you-create-different-variable-names-while-in-a-loop — DKDK, Nov 06 '20 at 17:11
Does this answer your question? [How do I create variable variables?](https://stackoverflow.com/questions/1373164/how-do-i-create-variable-variables) — Random Davis, Nov 06 '20 at 17:12
Check out this question too: https://stackoverflow.com/questions/4010840/generating-variable-names-on-fly-in-python/10182903 — , Nov 06 '20 at 17:12
Use a `list` for storing the result, instead of collection of variables. — Jan Christoph Terasa, Nov 06 '20 at 17:13

Cyrille Pontvieux · Answer 1 · 2020-11-07T00:01:48.430

1

for i in range(11):
  locals()[f'nfo{i + 1}'] = str(nfolist[i])

but it’s a bit ugly

edited Nov 07 '20 at 00:01

answered Nov 06 '20 at 17:11

Cyrille Pontvieux

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Wasif · Answer 2 · 2020-11-06T17:16:48.980

0

Instead you can use a dictionary:

nfo = {}
for x in range(11):
  nfo['nfo'+str(x)]=str(nfolist[x])

The dictionary nfo:

{'nfo0': '0',
 'nfo1': '1',
 'nfo2': '2',
 'nfo3': '3',
 'nfo4': '4',
 'nfo5': '5',
 'nfo6': '6',
 'nfo7': '7',
 'nfo8': '8',
 'nfo9': '9',
 'nfo10': '10'}

To get a value from the dict (suppose want nfo['nfo4']):

print(nfo['nfo4'])

edited Nov 06 '20 at 17:16

answered Nov 06 '20 at 17:11

Wasif

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How can I do it with for loop (Python)?

2 Answers2