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How to check if a given string has the same characters or their probability is the same, which gives me True?

For example, if there is string = "aaaa" the result is True and:

string = "aabb" True
string = "aabbcc" True
p = "1122" True
p = "aaaaBBBB9999$$$$" True

but:

string = "korara" False
p = "33211" False

For "aaa" I can use (len (set ("aaa")) == 1), but I don't know about the others.

0316
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    does this answer your question? https://stackoverflow.com/questions/991350/counting-repeated-characters-in-a-string-in-python – fdermishin Nov 07 '20 at 18:49

4 Answers4

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Have you try ?

from collections import Counter

def check(v):
    return len(set(Counter(v).values())) <= 1

assert check("aabb")
assert check("aabbcc")
assert check("1122")
assert check("aaaaBBBB9999$$$$")
assert check("")

assert not check("korara")
assert not check("33211")
arthurlm
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0

You can use the collection which will create a dictionary and then you can check for each value if they are equal.

The following piece of code does that:

import collections

counter = dict(collections.Counter("aabbcc"))

expected_value = next(iter(counter.values()))
are_equal = all(value == expected_value for value in counter.values())

print("Result for aabbcc: ", are_equal)

counter = dict(collections.Counter("korara"))

expected_value = next(iter(counter.values()))
are_equal = all(value == expected_value for value in counter.values())

print("Result for korara: ", are_equal)
Ergi Nushi
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0

Pass your string in this function

def repeating_probability(s):
    sarr={}
    for i in s:
        if i in sarr.keys():
            sarr[i] += 1
        else:
            sarr[i] = 1
    if len(list(set(sarr.values()))) == 1:
        return True
    else:
        return False
Tanmay Shrivastava
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-2

There's a length() function for strings though.

山の平和
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