How to scrape data like integer

Question

I need this list deneme=['/n 1991','/n 1993','/n 2020']

pure_deneme=["1991","1993","2020"] like this list and all values must be integer. Thanks.

Related: https://stackoverflow.com/questions/7368789/convert-all-strings-in-a-list-to-int — Tomerikoo, Nov 09 '20 at 13:26

score 1 · Accepted Answer · answered Nov 09 '20 at 13:17

1

Thats easy with list comprehensions:
if by '/n' you mean '\n' then you can simply do:

new_list = [int(element) for element in old_list]

if it is indeed '/n' you may have to do:

new_list = [int(element.replace('/n ', '')) for element in old_list]

This difference is because int() already knows how to ignore spaces and new lines ('\n'), but if there are other characters in there you will need to remove them with .replace('whatever', '')

answered Nov 09 '20 at 13:17

motrix

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Note that in case that the symbol is trailing (like here), you can use `strip` instead of `replace`: `int(element.strip('/n'))` – Tomerikoo Nov 09 '20 at 13:24
@motrix thanks it worked – Taylan Kol Nov 09 '20 at 21:44

How to scrape data like integer

1 Answers1