I have implemented in C++ print_in_binary_format() function, which (as the name states) print 8-bit number in binary:
void print_in_binary_format(std::uint8_t number)
{
for (int bit_index = 7; bit_index >= 0; --bit_index) {
std::cout << ((number & (1U << bit_index)) ? '1' : '0');
}
std::cout << '\n';
}
But it doesn't work as supposed, i.e.:
Input: 2
Output: 00110010
Input: 0
Output: 00110000
I know that in C++ I could use bitset library, but it is not the case.
I would like to know what is wrong with this function, my brain is stuck!
There is whole program to test that:
#include <cstdint>
#include <iostream>
std::uint8_t read_user_number();
void print_in_binary_format(std::uint8_t number);
int main()
{
std::uint8_t number {};
number = read_user_number();
print_in_binary_format(number);
return EXIT_SUCCESS;
}
std::uint8_t read_user_number()
{
std::cout << "Enter a number (0-255): ";
std::uint8_t user_number {};
std::cin >> user_number;
return user_number;
}
void print_in_binary_format(std::uint8_t number)
{
for (int bit_index = 7; bit_index >= 0; --bit_index) {
std::cout << ((number & (1U << bit_index)) ? '1' : '0');
}
std::cout << '\n';
}
