Regular Expression regex works in PHP but fails with errors in JS

Asked Nov 10 '20 at 21:38

Active Nov 10 '20 at 22:06

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So I have this regular expression...

(?i)\b[p]*(ost)*\.*\s*[o]*(ffice)*\.*(?<=po|p.o|o\.|office|post)\s*[b][o][x]\b|(?<=\d\s|^)\s*[[b][o][x]]*(?!\s*[a-z])|(?<=\d\s|^)\s*[[p][o]]*(?!\s*[a-z])

If you look at regex101.com and run the unit tests in PHP you can see all the tests match.

However, that same regex fails in JS.

Seems to be an issue with the first ? and possibly the use of look-backs? I might as well be looking at Japanese.

Is there an easy way to make this regex compatible with JS?

asked Nov 10 '20 at 21:38

RiddleMeThis

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Just use `i` flag in JS regex, no need to use the inline modifier that JS RegExp does not support. – Wiktor Stribiżew Nov 10 '20 at 21:39
I tried before to just take out the ? but the unit tests still fail, try and see. – RiddleMeThis Nov 10 '20 at 21:43
https://regex101.com/r/CuBLCO/7 – Wiktor Stribiżew Nov 10 '20 at 22:00
@WiktorStribiżew THANK YOU! Your a genius! Sorry this was closed so fast, you deserve credit for an aswer! – RiddleMeThis Nov 10 '20 at 22:03
But I [did answer](https://stackoverflow.com/a/37208514/3832970). Also, [this](https://stackoverflow.com/questions/3939715/case-insensitive-regex-in-javascript) is relevant – Wiktor Stribiżew Nov 10 '20 at 22:05

Regular Expression regex works in PHP but fails with errors in JS

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