how to print out a range with the single digit right justified

Question

For example, if I had a range of 10, it would print:

9
8
7

and so on. Then when I have double digits, so with a range of 11, it prints out:

10
9
8

But, I want it to print out with the 9 under the 0 instead. Any way to do this?

Does this answer your question? [How can I reverse a list in Python?](https://stackoverflow.com/questions/3940128/how-can-i-reverse-a-list-in-python) — Countour-Integral, Nov 12 '20 at 22:22
@Countour-Integral that is totally different than this question. This question is about right-justification, not list reversal. — Seth, Nov 12 '20 at 22:23

Sash Sinha · Accepted Answer · 2020-11-12T23:12:50.790

3

You could use str.rjust:

for i in reversed(range(1, 11)):
    print(str(i).rjust(2))

Output:

edited Nov 12 '20 at 23:12

answered Nov 12 '20 at 22:19

Sash Sinha

18,743
3
23
40

score 0 · Answer 2 · answered Nov 12 '20 at 22:19

0

In Python 3:

for i in range(11)[::-1]:
    print(f"{i:>2}")

If you want three-digit numbers, change the 2 to a 3.

answered Nov 12 '20 at 22:19

Seth

2,214
1
7
21

score 0 · Answer 3 · answered Nov 12 '20 at 22:21

You can just add a space at the beginning of the number. I just calculate the amount of digits and pad the lower number with spaces

max = 1337
max_len = len(str(max))
for i in reversed(range(max)):
    str_len = len(str(i))
    if max_len > str_len:
        difference = max_len - str_len #calculate amount of needed spaces
        print(" " * difference + str(i)) #pad string with spaces
    else:
        print(i)

how to print out a range with the single digit right justified

3 Answers3