How C# Method change the value of the parameter

Question

I am confused about how the code below works. Why is the output not 10 but 5?

public class Program
{
    public  void MyFunc(int x){
        x = 10;
    }
    public void Main()
    {
        int x = 5;
        MyFunc(x);
        Console.WriteLine(x);
    }
}

Thanks a lot.

`MyFunc(x)` does not pass `x` to `MyFunc`, it only passes the _value_ of `x`. See: https://stackoverflow.com/questions/5057267/what-is-the-difference-between-a-reference-type-and-value-type-in-c — Mathias R. Jessen, Nov 16 '20 at 15:20
Because x is passed by value, not by reference, so x in Main is never changed — Marco, Nov 16 '20 at 15:21

score 0 · Accepted Answer · answered Nov 16 '20 at 16:04

Read about the "ref keyword" Now result is 10


 public static void MyFunc(ref int x)
        {
            x = 10;
        }
        public static void Main()
        {
            int x = 5;
            MyFunc(ref x);
            Console.WriteLine(x);
        }

How C# Method change the value of the parameter

1 Answers1