bash script find nothing

Asked Nov 16 '20 at 17:57

Active Nov 16 '20 at 17:57

Viewed 18 times

my script should search for a file but it show nothing, here is the code from the 1. file:

#!/bin/bash
if [ "$1" == "" ]
then
        echo "search [options] file"
else
        /bin/search-help $1
fi

this is the code from the 2. file:

#!/bin/bash
find / -type d \( -path /proc -o -path */lost+found \) -prune -false -o -name '$1' & 
PID=$!
i=1
sp="/-\|"
printf "scanning  "
while [ -d /proc/$PID ]
do
        printf "\b${sp:i++%${#sp}:1}"
        sleep 0.1
done

asked Nov 16 '20 at 17:57

sereok

1

`$1` should be in double quotes, not single quotes. – Barmar Nov 16 '20 at 17:58
`it show nothing` `printf "scanning "` It doesn't even show "scanning"? – KamilCuk Nov 16 '20 at 17:59
And it should be quoted in the first script. – Barmar Nov 16 '20 at 17:59
When you fix the `find` command, the spinner won't work because the find output will overwrite it. You should probably redirect find to a file. – Barmar Nov 16 '20 at 18:02
@Barmar thank you that was the problem. KamilCuk you must execute the first script than it works and change the ' in the 2. script into " – sereok Nov 16 '20 at 18:05

bash script find nothing

0 Answers0