Exit function in python

Question

import random
import sys

player_oneN = input("Enter Name for Player One")
player_twoN = input("Enter Name for Player Two")
player_oneS = 0
player_twoS = 0
if player_oneN == "stop" or "exit":
    c = int(input("Press 1 to continue and 0 to quit :"))
    if c == 0:
        sys.exit()
if player_twoN == "stop" or "exit":
    c = int(input("Press 1 to continue and 0 to quit :"))
    if c == 0:
        sys.exit()

whenever I try to run this code the options to exit the program always displays. I only want this option to come available when the user enters exit or stop in the player one and player two input.

Does this answer your question? [or condition in while loop python](https://stackoverflow.com/questions/35994187/or-condition-in-while-loop-python) — lbragile, Nov 19 '20 at 04:57

Joe Ferndz · Answer 1 · 2020-11-19T05:41:33.633

Use in and check against a list of items when you want to check for multiple values in an if statement.

import random
import sys

player_oneN = input("Enter Name for Player One")
player_twoN = input("Enter Name for Player Two")
player_oneS = 0
player_twoS = 0
if player_oneN.lower() in ["stop", "exit"]: # replace with in list items
    c = int(input("Press 1 to continue and 0 to quit :"))
    if c == 0:
        sys.exit()
if player_twoN.lower() in ["stop", "exit"]: # replace with in list items
    c = int(input("Press 1 to continue and 0 to quit :"))
    if c == 0:
        sys.exit()

Since both your if statements are doing the same thing, you can combine them into one if statement.

if player_oneN.lower() in ["stop", "exit"] or player_twoN.lower() in ["stop", "exit"]:
    c = int(input("Press 1 to continue and 0 to quit :"))
    if c == 0:
        sys.exit()

You can also do something like this:

if any(i in ['stop','end'] for i in [player_oneN.lower(),player_twoN.lower()]):
    c = int(input("Press 1 to continue and 0 to quit :"))
    if c == 0:
        sys.exit()

score 2 · Answer 2 · answered Nov 19 '20 at 04:44

2

The problem is that player_twoN == "stop" or "exit" is not doing what you're expecting. Its being interpreted as (player_twoN == "stop") or "exit". Since a non-empty string evaluates to True, the whole statement evaluates to True.

answered Nov 19 '20 at 04:44

user0

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score 1 · Accepted Answer · answered Nov 19 '20 at 04:39

You or conditions are incorrect and just check that exit is not null which is always true.

import random
import sys

player_oneN = input("Enter Name for Player One")
player_twoN = input("Enter Name for Player Two")
player_oneS = 0
player_twoS = 0
if player_oneN == "stop" or player_oneN == "exit": # <--- should be this
    c = int(input("Press 1 to continue and 0 to quit :"))
    if c == 0:
        sys.exit()
if player_twoN == "stop" or player_twoN == "exit": # <--- should be this
    c = int(input("Press 1 to continue and 0 to quit :"))
    if c == 0:
        sys.exit()

Exit function in python

3 Answers3