Sort Dictionary without pandas

Question

I have a dictionary as follows:

test = {
    "Name": ["Bimal", "Kamal", "Hari", "Ram", "Shyam"],
    "Age": [12, 24, 23, 19, 17]
}

and I want to sort it based on name so that the age of Kamal must remain 24 after sorting. So, what I want as final dictionary is:

test = {
    "Name": ["Bimal", "Hari", "Kamal", "Ram", "Shyam"],
    "Age": [12, 23, 24, 19, 17]
}

I can easily do it with pandas but I wanted an efficient way to do it without using pandas. Is there any way to do it efficiently?

Answer 1

You could use zip method.

test = {
   "Name": ["Bimal", "Kamal", "Hari", "Ram", "Shyam"],
   "Age": [12, 24, 23, 19, 17]
}

print(*zip(*sorted(zip(test["Name"], test["Age"]))))

The result of this will consists in two tuples and then you can convert to lists.

result = list(zip(*sorted(zip(test["Name"], test["Age"]))))
test = {
  "Name": list(result[0]),
  "Age": list(result[1])
}