Dictionary - How to map list of KEY with list of VALUE?

Question

I have two different list:

key = ['key1', 'key2', 'key3']
value = ['value1', 'value2', 'value3']

I want to map it like this :

dictionary = {'key1':'value1',
              'key2':'value2',
              'key3':'value3'}

I tried this:

dictionary = {key, value}

But I got this result:

TypeError: dict expected at most 1 arguments, got 2

Please search on stack overflow before asking: https://stackoverflow.com/questions/209840/convert-two-lists-into-a-dictionary — Harsha Biyani, Nov 19 '20 at 07:26

score 7 · Accepted Answer · answered Nov 19 '20 at 07:24

7

Do this to get the desired result,

dictionary = dict(zip(key, value))

answered Nov 19 '20 at 07:24

Sreeram TP

1

Using `zip` is a good way of preserving the order of key, value items from the lists. – InsertCheesyLine Nov 19 '20 at 07:26

score 1 · Answer 2 · answered Nov 19 '20 at 07:26

1

Try this :

dictionary = {key[i]:value[i] for i in range(len (key))}

This is what is called a dictionary comprehension.

Essentially what you are doing is looping through the indexes and accessing the various values at the dictionary.

This might help

answered Nov 19 '20 at 07:26

Benjamin Philip

score 0 · Answer 3 · answered Nov 19 '20 at 07:25

0

res = {key[i]: value[i] for i in range(len(key))}

answered Nov 19 '20 at 07:25

Carl H

3 Answers3