Regular expression and \n EOL on the end of tested string

Asked Nov 19 '20 at 17:33

Active Nov 19 '20 at 18:45

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I have simple regex ^[a-zA-Z0-9,. ]*$

I test it in .NET like this:

Regex.IsMatch(description, @"^[a-zA-Z0-9,. ]*$")

I do not understand why when there is "\n" EOL char on the end of the string then why this string matches. Or - how should the correct regex that is ignoring \n on the end would look like?

Examples:

"abc .123," - matches

"abc .123,\n" - matches, but WHY?

"abc\n .123," - does not match

But if I test this regex e.g. on http://regexstorm.net/tester the same string with \n on the end DOES NOT match (which I hope is correct).

Thank You all.

asked Nov 19 '20 at 17:33

Miroslav Vanický

Probably related: https://stackoverflow.com/a/60730367/ – VLAZ Nov 19 '20 at 17:38
Just trim-end the NL – dcg Nov 19 '20 at 17:40
Use `\z` instead of `$`. – Wiktor Stribiżew Nov 19 '20 at 18:43
You regex matches empty lines. The text ending with `\n` has two lines with second one being empty so it matches no matter what you put in front of the `\n` – wqw Nov 19 '20 at 20:55

Regular expression and \n EOL on the end of tested string

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