awaiting a value from a async function with setTimeOut and Promise

Question

So I have this famous function from the documentation.

function resolveAfter2Seconds(x) {
  return new Promise(resolve => {
    setTimeout(() => {
      resolve(x);
    }, 2000);
  });
}

How should I rewrite it so when I type console.log(resolveAfter2Seconds(10)) I would get a result not Promise {Pending} in the console? The first bit is probably easy - putting async in front. But what next?

score 0 · Answer 1 · answered Nov 21 '20 at 14:46

0

dont you need

resolveAfter2Seconds(1).then(c=>console.log(c))

answered Nov 21 '20 at 14:46

ubaidh khatlani

92
1
8

According to the requirement provided to me I have to use async/await. – retro Nov 21 '20 at 15:13
1

```(async ()=>{ let c =await resolveAfter2Seconds(34) console.log(c)})()``` – ubaidh khatlani Nov 21 '20 at 15:49
1

Thanks, I came up with something similar `async function msg() { const msg = await ResolveAfter2Seconds(10); console.log('Message:', msg); } msg(); ` – retro Nov 21 '20 at 15:56
yes you used named function. but why did you use the same name for function and variable .thanks – ubaidh khatlani Nov 21 '20 at 16:01

awaiting a value from a async function with setTimeOut and Promise

1 Answers1