how to find only words after equal character with regex?

Question

For example, in this text:

source=sourses/date=2018-02-05
date=2018-02-05/source=swbsource
flight_source=soursewft/date=2018-02-05
date=2018-02-05/source=sources
source=sourseswqa/date=2018-02-05
date=2018-02-05/flight_source=sourcepdt

I want to match the only words after equal. I mean the only sourseswqa, swbsource, sources, sourcepdt, sourses, soursewft words. but it could not be only 'source' or 'flight_source'

Shazi · Accepted Answer · 2020-11-25T00:16:22.953

-1

Let's break it down: According to your description, you are interested in the first word following an equals character when the equals character follows the word "source" or "flight_source". The captured word is then terminated by a whitespace character, a forward slash or the end of the string.

A regex similar to this should do the trick:

(?:flight_source|source)=([^\/\s]+)

The first group is a non capturing group that matches either "source" or "flight_source". We then look for an equals sign. After finding an equals sign we start a capturing group where we capture one or more characters that are NOT a forward slash or a whitespace character.

edited Nov 25 '20 at 00:16

answered Nov 25 '20 at 00:05

Shazi

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Your regex is right but i need to get only words, without flight_source or source I mean only sourseswqa not a source=sourseswqa – Andriy Skyba Nov 25 '20 at 00:20
Yes, and you should have that within your captures – Shazi Nov 25 '20 at 00:22
I'm trying it now but get source=sourseswqa – Andriy Skyba Nov 25 '20 at 00:23
Thats because you need to extract the captured group from the regex match. You can read more about capture groups on https://regexone.com/lesson/capturing_groups – Shazi Nov 25 '20 at 00:29

how to find only words after equal character with regex?

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