SwiftUI observed object do action when its property change

Question

I have observed object which is created in view and I want to have function that will occur when the object bool property is changed. I want something similar to .onTapGesture. Is there a way to do it? have function where the body of the function is created outside of that object?

How is this function related to the view, is it tied to some component? — Joakim Danielson, Nov 26 '20 at 15:10

score 8 · Answer 1 · answered Nov 26 '20 at 15:33

8

Let's replicate...

class Demo: ObservableObject {
   @Published var value = false
}

struct DemoView: View {
   @ObservedObject var demo = Demo()

   var body: some View {
      Text("Demo") 
        .onReceive(demo.$value) { flag in
            // call here your function
        }
   }
}

answered Nov 26 '20 at 15:33

Asperi

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690

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Is there a way I could pass array of observed objects? – K. Ondřej Nov 26 '20 at 16:54

score 0 · Answer 2 · answered May 18 '21 at 17:27

0

use @ObservedObject to make change in value an use @StateObject to read the published value

answered May 18 '21 at 17:27

Admiral

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3

SwiftUI observed object do action when its property change

2 Answers2