How to access the individual items in a variable in Windows Batch?

Question

I have this list in batch:

set list=12,34,56
echo %list%

How can I get the list to print only 34?

See my answer [here](https://stackoverflow.com/a/64762748/12343998) for a means of access elements of a list by index. — T3RR0R, Nov 27 '20 at 03:34
@aschipfl With all due respect, the question linked as duplicate is like recommending a sledgehammer to kill a fly ;-) [How to loop through comma separated string in batch?](https://stackoverflow.com/questions/17158719/how-to-loop-through-comma-separated-string-in-batch) may be a closer match. — dxiv, Nov 28 '20 at 06:47
I see, @dxiv, you're right; once I'm at a computer I'll add the link you're suggested (it can't be done via mobile)… — aschipfl, Nov 28 '20 at 12:45

score 2 · Accepted Answer · answered Nov 27 '20 at 03:46

To print the second number 34:

for /f "tokens=2 delims=," %%a in ("%list%") do @echo %%a

To print all 3 numbers 12 34 56:

for /f "tokens=1-3 delims=," %%a in ("%list%") do @echo %%a %%b %%c

The double percents in %%a are required in a batch file. At the command prompt, use just %a.

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