Paste0, subset Error: 'subset' must be logical

Asked Nov 27 '20 at 15:29

Active Nov 27 '20 at 15:32

Viewed 1,217 times

I would like to use paste0 to create a long string containing the conditions for the subset function.

I tried the following:

#rm(list=ls())
set.seed(1)
id<-1:20
ids<-sample(id, 3)
 
 d <- subset(id, noquote(paste0("id==",ids,collapse="|")))

I get the

Error in subset.default(id, noquote(paste0("id==", ids, collapse = "|"))) : 
  'subset' must be logical

I tried the same without noquote. Interestinly when I run

noquote(paste0("id==",ids,collapse="|"))

I get [1] id==4|id==7|id==1. When I then paste this by hand in the subset formula

d2<-subset(id,id==4|id==7|id==1)

Everything runs nice. But why does subset(id, noquote(paste0("id==",ids,collapse="|"))) not work although it seems to be the same? Thanks a lot for your help!

edited Nov 27 '20 at 15:32

zx8754

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asked Nov 27 '20 at 15:29

FicusBenji

2

Why not just `subset(id, id %in% ids)` or `id[id %in% ids]`? – ekoam Nov 27 '20 at 15:32
Maybe `subset(id, eval(parse(text = paste0("id==", ids, collapse="|"))))` ? – zx8754 Nov 27 '20 at 15:40
Possible duplicate of https://stackoverflow.com/q/1743698/680068 – zx8754 Nov 27 '20 at 15:40
`noquote` just changes the print method for a string. It does not force evaluation of a string as an expression. – bcarlsen Nov 27 '20 at 15:57
Thanks a lot! Both versions work well. – FicusBenji Nov 27 '20 at 16:27

Paste0, subset Error: 'subset' must be logical

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