Single instance of firebase

Question

How to get single instance of firebase in android throughout application. Iam getting instance from class.whlie trying to do from module level am getting fail.

Class firebasemodule{
     Var module = module{ 
   singlee(createdatstart=true){ 
     gett<Firebase>().instance}}
}
In app level class
Startkoin{ module(listof(firebasemodule))}

Here am getting error.

Any suggestion accepted and I would be helpful for me and for many also.

could you fix the syntax in your example first? e.g. `class` `single` `get` etc.. — JensV, Nov 30 '20 at 16:27
Does this answer your question? [Singleton class in Kotlin](https://stackoverflow.com/questions/51834996/singleton-class-in-kotlin) — Ryan M, Nov 30 '20 at 23:47

score 0 · Accepted Answer · answered Nov 30 '20 at 21:00

0

You should use

class FirebaseModule {
    val module = module {
        single {
            FirebaseFirestore.getInstance()
        }
    }
}

answered Nov 30 '20 at 21:00

AndroidEngineX

975
1
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It's simple and very quick solution – Code Learner. Dec 07 '20 at 17:32
If don't want to take instance in this module , we can create seperate class for firebase and call that class in module. ''' class FirebaseModule { val module = module { single { FirebaseHandler() } } } Class FirebaseHandler(){ Firebase.getInstance(). } ''' – Code Learner. Dec 07 '20 at 17:41

score 0 · Answer 2 · edited Dec 10 '20 at 13:43

0

If don't want to take instance in this module , we can create seperate class for firebase and call that class in module.

class FirebaseModule {
    val module = module {
        single {
            FirebaseHandler()
        }
    }
}
class FirebaseHandler(){
   val firebase = Firebase.getInstance()
}

edited Dec 10 '20 at 13:43

AndroidEngineX

975
1
9
22

answered Dec 07 '20 at 17:45

Code Learner.

61
9

Single instance of firebase

2 Answers2