Round function in math.h is giving an incorrect output

Asked Dec 01 '20 at 08:40

Active Dec 01 '20 at 08:52

Viewed 156 times

#include<stdio.h>
#include<math.h>

int main(void)
{
    printf("%f", round((27 + 28 + 28)/3));
}

The roundoff is 28 but it is giving an output of 27. Please help

asked Dec 01 '20 at 08:40

rktejesh

4

This is because of **integer division**. `83 / 3` is `27` and passing to `round()` has no effect. – Weather Vane Dec 01 '20 at 08:47
1

`round((27 + 28 + 28)/3.0 ) = 28` – Krishna Kanth Yenumula Dec 01 '20 at 08:56
1

use --> round((27. + 28. + 28.)/3.)); – Florent Dec 01 '20 at 09:29
I just would like to add that type matters, so keep it in mind while you are doing maths in C or any other programming language. Focus in what kind of data type you want as a result and convert or type any operand to that specific type, which will avoid many issues. – Carles Dec 01 '20 at 09:39
@WeatherVane Thanks I got it. So if one divides the integer by integer they get the integer value. – rktejesh Dec 01 '20 at 10:11

0 Answers0