How do I get only the first number without brackets in a list?

Question

I have a list l1 this is structured according to the scheme [(number1, number2), ... (number1n, number2n]. I would like to always only want the very first number and remove the brackets. How do I do that?

l1 = [(285, 1.0000001), (3614, 0.93460923), (671, 0.78742), (1351, 0.72903967), (3883, 0.6139718)]
l2 = [285, 3614, 671, 1351, 3883]

If you had just `(number1, number2)`, would you know how to get `number1` out of that? — Karl Knechtel, Dec 02 '20 at 09:23
Does this answer your question? [Transpose/Unzip Function (inverse of zip)?](https://stackoverflow.com/questions/19339/transpose-unzip-function-inverse-of-zip) — buran, Dec 02 '20 at 09:24
Top! Quickly and correctly, thank you very much. Have a wonderful day. — Ella, Dec 02 '20 at 09:24

Mehrdad Pedramfar · Accepted Answer · 2020-12-02T09:26:23.570

3

Try this:

l1 = [(285, 1.0000001), (3614, 0.93460923), (671, 0.78742), (1351, 0.72903967), (3883, 0.6139718)]


l2 = [i[0] for i in l1]

or

l2 = [i for i,j in l1]

Also you can do it with zip.

l2 = list(zip(*l1))[0]

Using map:

l2 = list(map(lambda x:x[0], l1))

edited Dec 02 '20 at 09:26

answered Dec 02 '20 at 09:23

Mehrdad Pedramfar

10,941
4
38
59

How do I get only the first number without brackets in a list?

1 Answers1