Replacing text with blanks OSX Sed

Question

My file has 2 times stamps in every line. I would like to delete the +0800 in every line using sed. I have tried the following command labelled "command used"

Example input    
2020-11-17 08:50:42.614276+0800 2020-11-17 08:50:42.000000+0800

Command used
sed -E 's/\+\d{4}//g'

Actual Output (same as input)
2020-11-17 08:50:42.614276+0800 2020-11-17 08:50:42.000000+0800

Expected Output
2020-11-17 08:50:42.614276 2020-11-17 08:50:42.000000

score 0 · Accepted Answer · answered Dec 04 '20 at 04:41

0

Use

sed -E 's/\+[0-9]{4}//g'

or

sed -E 's/\+[[:digit:]]{4}//g'

instead, as sed does not recognize \d.

answered Dec 04 '20 at 04:41

Diego Torres Milano

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Thanks for this! It didn't even throw an error so I thought it would be ok. So would the regex have been searching for "\d" in the pattern space – KOOTS HOOTS Dec 04 '20 at 05:25
And as you can verify `grep -E '\+\d{4}'` works – Diego Torres Milano Dec 04 '20 at 06:19

Replacing text with blanks OSX Sed

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