C++ Error: no matching function for call to 'reverse(char*&)'

Asked Dec 05 '20 at 22:23

Active Dec 05 '20 at 22:25

Viewed 392 times

I'm trying to make code for converting a base4 number into a base2 number. Here is the code:

#include <iostream>
#include <cstdlib>
#include <iomanip>
#include <bits.h>
#include <algorithm>
using namespace std;

 void itoa(int n, char s[])
 {
     int i, sign;

     if ((sign = n) < 0)
         n = -n;
     i = 0;
     do {
         s[i++] = n % 10 + '0';
     } while ((n /= 10) > 0);
     if (sign < 0)
         s[i++] = '-';
     s[i] = '\0';
     reverse(s);
 }

At the end, there is a reverse function. When I run the code, the error in the title appears. I don't know what to do about this. Thanks in advance!

edited Dec 05 '20 at 22:25

463035818_is_not_an_ai

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asked Dec 05 '20 at 22:23

jedraszek

1

what reverse function do you mean? – 463035818_is_not_an_ai Dec 05 '20 at 22:24
https://en.cppreference.com/w/cpp/algorithm/reverse – Shawn Dec 05 '20 at 22:26
please include that in the question – 463035818_is_not_an_ai Dec 05 '20 at 22:27
2

I assume you are trying to use `std::reverse` from the `` standard library module. Please [read the documentation](https://en.cppreference.com/w/cpp/algorithm/reverse) to see how to call it. – Karl Knechtel Dec 05 '20 at 22:28
Or are you trying to use the new [`ranges::reverse()`](https://en.cppreference.com/w/cpp/algorithm/ranges/reverse)? – Shawn Dec 05 '20 at 22:28
1

Does this answer your question? [Is there a standard C++ iterator for C strings?](https://stackoverflow.com/questions/51770586/is-there-a-standard-c-iterator-for-c-strings) – Karl Knechtel Dec 05 '20 at 22:29
1

Nitpick: It's not when you run the code but when you compile the code that the error happens. – Ulrich Eckhardt Dec 05 '20 at 22:31

C++ Error: no matching function for call to 'reverse(char*&)'

0 Answers0