Python3 - How to detect mouse clicked on the image or not in pygame

Question

I am making a game and i want to get image position which i have placed in center i tried image.get_rect() but it returned me the image rectangle size

My Code as follows:

import pygame
import random # for random line color
import pygame.mouse

# Random color script
a = random.randrange(1,255,1)
b = random.randrange(1,255,1)
c = random.randrange(1,255,1)
linecolor = a, b, c
#a bunch of variables
bgcolor = 0, 0, 0
x = y = 0
LEFT = 1
running = 1
s = 0

h, w = 640, 400

screen = pygame.display.set_mode((h, w))
# defining image
image = pygame.image.load( "DK.bmp" )
imagePosition = image.get_rect()
imagePosition.bottom = 200
imagePosition.left = 300
screen.blit( image, imagePosition )

pygame.mixer.init()
shot = pygame.mixer.Sound("shot.wav")
         

while running:
     event = pygame.event.poll()
     pygame.display.init()
     # font stuff
     pygame.font.init()
     fontDefault = pygame.font.Font( None, 48 )
     fontScoot = pygame.font.Font("scootchover-sans.ttf",24)
     
     pygame.event.pump()
     pygame.mouse.set_visible(0)
     
     if event.type == pygame.QUIT:
          running = 0
     elif event.type == pygame.MOUSEMOTION:
          x, y = event.pos
     elif event.type == pygame.MOUSEBUTTONDOWN and event.button == LEFT:
          s = s + 1 # number of shots fired
          shot.play()
          x, y = pygame.mouse.get_pos()

          if image.get_rect().collidepoint(x, y):
               print('clicked on image')

     
     # score board color variables and "if" statements:
     s1 = 66
     s2 = 66
     s3 = 66
     if s > 99:
          s1 = 0
          s2 = 120
          s3 = 0
     if s > 199:
          s1 = 255
          s2 = 120
          s3 = 0
     if s  > 299:
          s1 = 187
          s2 = 0
          s3 = 0
     if s > 399:
          s1 = 255
          s2 = 255
          s3 = 0
     if s > 499:
          s1 = 0
          s2 = 0
          s3 = 255
     if s > 599:
          s1 = 0
          s2 = 255
          s3 = 0
     if s > 699:
          s1 = 128
          s2 = 255
          s3 = 255
     if s > 799:
          s1 = 64
          s2 = 128
          s3 = 128
     if s > 899:
          s1 = 255
          s2 = 255
          s3 = 255
     if s > 999:
          # score board
          s1 = random.randrange(1,255,1)
          s2 = random.randrange(1,255,1)
          s3 = random.randrange(1,255,1)
          # aimer
          a = random.randrange(1,255,1)
          b = random.randrange(1,255,1)
          c = random.randrange(1,255,1)
          linecolor = a, b, c
          ya = random.randrange(1,6,1)
          if ya == 1:
               image = pygame.image.load( "ya.bmp" )
          if ya == 2:
               image = pygame.image.load( "ya2.bmp" )
          if ya == 3:
               image = pygame.image.load( "ya3.bmp" )
          if ya == 4:
               image = pygame.image.load( "ya4.bmp" )
          if ya == 5:
               image = pygame.image.load( "ya5.bmp" )
          if ya == 6:
               image = pygame.image.load( "ya6.bmp" )
     score = fontScoot.render( "Score: " + str(s),1, (s1,s2,s3))
     if s > 999:
          score = fontScoot.render( "OMG!! YOU SCORE IS " + str(s),1, (s1,s2,s3))
     if s > 1999:
          score = fontScoot.render( "HOLY F*CKING SH*T!! YOU SCORE IS " + str(s),1, (s1,s2,s3))

     pygame.display.set_caption("Shooter")

     screen.blit( score, (500,100) )
     screen.fill(bgcolor)
     screen.blit( image, imagePosition )
     pygame.draw.line(screen, linecolor, (x, 0), (x, 399))
     pygame.draw.line(screen, linecolor, (0, y), (639, y))
     screen.blit( score, (100,100) )
     pygame.display.flip()

My Code includes some images and all so i have uploaded whole images and all on this link I Am using python 3.8 & I am on linux

score 1 · Accepted Answer · answered Dec 06 '20 at 16:48

pygame.Surface.get_rect.get_rect() returns a rectangle with the size of the Surface object, that always starts at (0, 0) since a Surface object has no position. The position of the rectangle can be specified by a keyword argument. For example, the center of the rectangle can be specified with the keyword argument center. These keyword argument are applied to the attributes of the pygame.Rect before it is returned (see pygame.Rect for a full list of the keyword arguments).

You have already set the image rectangle to imagePosition. Use imagePosition rather than image.get_rect():

while running:
    # [...]

    for event in pygame.event.get():
        if event.type == pygame.QUIT:
            running = 0
        elif event.type == pygame.MOUSEMOTION:
            x, y = event.pos
        elif event.type == pygame.MOUSEBUTTONDOWN and event.button == LEFT:
            s = s + 1 # number of shots fired
            shot.play()
            if imagePosition.collidepoint(event.pos):
                print('clicked on image')

score -1 · Answer 2 · edited Dec 06 '20 at 16:47

-1

Here try this

def on_click(event=None):
    # `command=` calls function without argument
    # `bind` calls function with one argument
    print("image clicked")

edited Dec 06 '20 at 16:47

a121

798
4
9
20

answered Dec 06 '20 at 16:41

Your Friendly Devloper

1
2

PyGame has no `on_click` event. Don't confuse [PyGame](https://www.pygame.org/news) with [Pygame Zero](https://pygame-zero.readthedocs.io/en/stable/) – Rabbid76 Dec 06 '20 at 16:48

Python3 - How to detect mouse clicked on the image or not in pygame

2 Answers2