Python list temproray variable or seperate items

Question

I've been looking for the answer to this question for a long time, but I couldn't find a solution. I am waiting for your help, thank you in advance. With python

list1 = ["data1","data2","data3","data4","data5"]

output = [    
[list1[0],list1[1]],
[list1[2],list1[3]],
[list1[4]]
        ]
output=[["data1","data2"],["data3","data4"],["data5"]]

How can it provide this output? Can I create a temporary variable in a list and do that.

This code does exactly what you want. What is your question? — John Gordon, Dec 06 '20 at 17:13
You can do something like: `[list1[i:i+2] for i in range(0, len(list1), 2)]` — juanpa.arrivillaga, Dec 06 '20 at 17:26

score 1 · Accepted Answer · answered Dec 06 '20 at 17:19

1

list1 = ["data1","data2","data3","data4","data5"]
out = []
i = 0

while True:

    #print("i", i)

    if i == len(list1)-1:
        out.append([list1[-1]])
        break
    elif i > len(list1)-1:
        break
    else:
        out.append([list1[i], list1[i+1]])
    i += 2
print(out)

answered Dec 06 '20 at 17:19

Shan Ali

564
4
12

Not pythonic but a valid solution. – juanpa.arrivillaga Dec 06 '20 at 17:25

score 0 · Answer 2 · answered Dec 06 '20 at 17:11

0

You are correct. If you print output (e.g. print(output) ) you get

[['data1', 'data2'], ['data3', 'data4'], ['data5']]

which is what your are looking for.

'Output' will be a list of lists which is allowed in python.

answered Dec 06 '20 at 17:11

Franco

441
3
18

Python list temproray variable or seperate items

2 Answers2