Execute application/x-executable file using python code

Question

First of all, I'm new to coding and I''ve tried a lot to understand this problem but I'm stuck. So, I have an executable (application/x-executable) file that I need to run in python code(not from command prompt). In command prompt it is working by:

$ ./test
> add filename.xml

So, what I did is I used subprocess module and I guess it is working.

import subprocess
subprocess.call('./test')

Now I need to pass arguments, Im trying to

subprocess.run('add fielname.xml', shell=True)

It is giving the following error

/bin/sh: 1: add: not found

Appreciate any hint or help!

I think that maybe this way you solve ```subprocess.run(["./test"],input=b"add filename.xml")```, but I'm not sure. Could try it? — Gealber, Dec 07 '20 at 15:40
`add filename.xml` isn't an argument, it's stdin. It would be an _argument_ if you ran `./test add filename.xml` at your prompt. — Charles Duffy, Dec 07 '20 at 19:51

score 0 · Accepted Answer · answered Dec 07 '20 at 19:50

0

You can do it in this way

subprocess.run(["./test"],input=b"add filename.xml")

answered Dec 07 '20 at 19:50

Gealber

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In [How to Answer](https://stackoverflow.com/help/how-to-answer), note the *Answer Well-Asked Questions* section, and therein the bullet point regarding questions that "have been asked and answered many times before" – Charles Duffy Dec 07 '20 at 19:53
You are right, didn't know about that. – Gealber Dec 07 '20 at 21:37

Execute application/x-executable file using python code

1 Answers1