In Python 3.7, time_ns() gives epoch timestamp in nanoseconds. How can it be got in 3.6.9?
When I use time(), it gives me seconds.
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phileoseda
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That should be resolvable with simple math. – Klaus D. Dec 08 '20 at 07:19
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Maybe this will help you: https://stackoverflow.com/questions/2394485/get-posix-unix-time-in-seconds-and-nanoseconds-in-python – Sharmiko Dec 08 '20 at 08:04
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1`time()` returns a floating point number, so it is much more precise than seconds. You just need to multiply it. – zvone Dec 08 '20 at 08:06
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You can't get nanosecond accuracy even using time_ns(). It's better than time(), but still not real nano-second accuracy.
Take a look at PEP-564 (https://www.python.org/dev/peps/pep-0564/#annex-clocks-resolution-in-python) - maybe you can just multiply by 1e9 and get a satisfactory result.
Radek
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1`time()` and `time_ns()` are using the same underlying function to get the time. The only difference is that one returns a floating point and the other returns an integer. The precision (of both of them) depends on the operating system. – zvone Dec 08 '20 at 08:25
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The link that I posted contains a resolution analysis. I suppose you didn't open it, so here is the summary: "The resolution of time.time_ns() is much better than time.time(): 84 ns (2.8x better) vs 239 ns on Linux and 318 us (2.8x better) vs 894 us on Windows." – Radek Dec 08 '20 at 08:42