ZGrep for first occurence of pattern after given line

Question

so I know that to find the line number of the first occurrence of a pattern in a file I do:

zgrep -n -m 1 "pattern" big_file.txt.gz

but what If I want to skip the first 500K lines? (I can't decompress the file. It's too large.)

Try: `gzcat big_file.txt.gz | awk 'NR > 500000 && /pattern/ {print NR ":" $0; exit}'` — anubhava, Dec 08 '20 at 21:50

score 2 · Accepted Answer · answered Dec 08 '20 at 22:02

2

You may use this gzcat | awk command:

gzcat big_file.txt.gz |
awk 'NR > 500000 && /pattern/ {print NR ":" $0; exit}'

answered Dec 08 '20 at 22:02

anubhava

1

On some Unix version `gzcat` is different from `zcat`. `gzcat` is for `.gz` files and `zcat` is for `.z` (zipped) files – anubhava Dec 08 '20 at 22:13

ZGrep for first occurence of pattern *after* given line