How to create a list with the elements that exist in both lists

Question

list1 = ["aaa", "bba", "bb"]
list2 = ["aav", "bb", "ace"]
list3 = (the elements in list1 and list2) 
list4 = (the elements in list1 but not in list2)

So, I have 2 lists here and I want to check the elements that are in both lists and the elements that exist in list1 and not in list2

Does this answer your question? [Common elements comparison between 2 lists](https://stackoverflow.com/questions/2864842/common-elements-comparison-between-2-lists) — shaik moeed, Dec 10 '20 at 07:49

score 3 · Answer 1 · answered Dec 10 '20 at 07:47

3

use list comprehension.

list3 = [item for item in list1 if item in list2]
list4 = [item for item in list1 if item not in list2]

answered Dec 10 '20 at 07:47

sudonym

3,788
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ppwater · Answer 2 · 2020-12-12T12:37:48.607

Try using sets. Like this:

list1 = ["aaa", "bba", "bb"]
list2 = ["aav", "bb", "ace"]
list3 = list(set(list1) & set(list2))
list4 = list(set(list1) - set(list2))
print(list3)
print(list4)

Or same as above, but using set functions:

list1 = ["aaa", "bba", "bb"]
list2 = ["aav", "bb", "ace"]
list3 = list(set(list1).intersection(set(list2))) # same as &
list4 = list(set(list1).difference(set(list2))) # same as -
print(list3)
print(list4)

score 1 · Answer 3 · answered Dec 10 '20 at 07:48

1

In [8]: list1 = ["aaa", "bba", "bb"]
   ...: list2 = ["aav", "bb", "ace"]

In [9]: set(list1) & set(list2)
Out[9]: {'bb'}

In [10]: set(list1) - set(list2)
Out[10]: {'aaa', 'bba'}

answered Dec 10 '20 at 07:48

idar

614
6
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How to create a list with the elements that exist in both lists

3 Answers3